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(D) To find the approximate value,we round the percentages and numbers:$71.98 \% \approx 72 \%$$35.06 \% \approx 35 \%$The equation becomes:$72 \% 	e

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$160$

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(D) To find the approximate value,we round the percentages and numbers:$71.98 \% \approx 72 \%$$35.06 \% \approx 35 \%$The equation becomes:$72 \% 	ext{ of } 1200 + 35 \% 	ext{ of } 270 = x \% 	ext{ of } 600$Calculate the values:$72 \% 	ext{ of } 1200 = 0.72 	imes 1200 = 864$$35 \% 	ext{ of } 270 = 0.35 	imes 270 = 94.5$Summing these values:$864 + 94.5 = 958.5$Now,solve for $x$:$958.5 = \frac{x}{100} 	imes 600$$958.5 = 6x$$x = \frac{958.5}{6} = 159.75$Rounding to the nearest whole number,we get $x \approx 160$.

What approximate value will come in place of the question mark $(?)$ in the given question? (You are not expected to calculate the exact value)
$71.98 \%$ of $1200 + 35.06 \%$ of $270 = ? \%$ of $600$

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What approximate value will come in place of the question mark $(?)$ in the given question? (You are not expected to calculate the exact value)$71.98 \%$ of $1200 + 35.06 \%$ of $270 = ? \%$ of $600$