What are X and Y in the following reaction?Pe | vedclass

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(A) The reaction of $Pent-2-ene$ $(CH_3-CH_2-CH=CH-CH_3)$ with ozone $(O_3)$ followed by reductive cleavage with $Zn/H_2O$ is known as ozonolysis.In t

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$X$$Y$$CH_3CHO$$CH_3CH_2CHO$

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(A) The reaction of $Pent-2-ene$ $(CH_3-CH_2-CH=CH-CH_3)$ with ozone $(O_3)$ followed by reductive cleavage with $Zn/H_2O$ is known as ozonolysis.In this reaction,the double bond is cleaved to form two carbonyl compounds.$CH_3-CH_2-CH=CH-CH_3 \xrightarrow[(ii) Zn / H_2O]{(i) O_3} CH_3-CH_2-CHO + CH_3-CHO$Here,$CH_3-CH_2-CHO$ is $Propanal$ and $CH_3-CHO$ is $Ethanal$.Thus,$X$ and $Y$ are $CH_3CHO$ and $CH_3CH_2CHO$ respectively.

What are $X$ and $Y$ in the following reaction?
$Pent-2-ene \xrightarrow[(ii) Zn / H_2O]{(i) O_3} X + Y$

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What are $X$ and $Y$ in the following reaction?$Pent-2-ene \xrightarrow[(ii) Zn / H_2O]{(i) O_3} X + Y$