Class 11Physics1 Thermal Properties of Matter: Thermometry, Expansion and CalorimetryMix Examples-Thermometry, Thermal Expansion and Calorimetry
MediumWhat are freezing and freezing point?
(N/A) Freezing is the phase transition process in which a substance changes from a liquid state to a solid state. This occurs when the thermal energy of the molecules decreases,causing them to lose their mobility and arrange themselves into a fixed,ordered structure.
The freezing point is the specific temperature at which a liquid turns into a solid at a given pressure. At this temperature,the liquid and solid phases of the substance exist in thermal equilibrium. For pure water at standard atmospheric pressure $(1.013 \times 10^5 \ Pa)$,the freezing point is $0 \ ^\circ C$ or $273.15 \ K$.
The freezing point is the specific temperature at which a liquid turns into a solid at a given pressure. At this temperature,the liquid and solid phases of the substance exist in thermal equilibrium. For pure water at standard atmospheric pressure $(1.013 \times 10^5 \ Pa)$,the freezing point is $0 \ ^\circ C$ or $273.15 \ K$.
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$A$ block of steel of mass $2 \,kg$ slides down a rough inclined plane of inclination $\sin ^{-1}\left(\frac{3}{5}\right)$ at a constant speed. Assuming that the mechanical energy lost due to friction is used to increase the temperature of the block, calculate the rise in temperature of the block as it slides through $80 \,cm$. (Specific heat capacity of steel $= 420 \,J kg^{-1} K^{-1}$ and acceleration due to gravity $= 10 \,ms^{-2}$) (in $^{\circ} C$)
$Assertion :$ In the pressure-temperature $(P-T)$ phase diagram of water,the slope of the melting curve is found to be negative.
$Reason :$ Ice contracts on melting to water.
$Reason :$ Ice contracts on melting to water.
Thermal expansion due to an increase in temperature...
Medium
View SolutionOut of the following,in which vessel will the temperature of the solution be higher after the salt is completely dissolved?
Easy
View SolutionHeat energy of $184\,kJ$ is given to ice of mass $600\,g$ at $-12^{\circ}\,C$. The specific heat of ice is $2222.3\,J\,kg^{-1\circ}C^{-1}$ and the latent heat of fusion of ice is $336\,kJ\,kg^{-1}$.
$(A)$ Final temperature of the system will be $0^{\circ}C$.
$(B)$ Final temperature of the system will be greater than $0^{\circ}C$.
$(C)$ The final system will have a mixture of ice and water in the ratio of $5:1$.
$(D)$ The final system will have a mixture of ice and water in the ratio of $1:5$.
$(E)$ The final system will have water only.
Choose the correct answer from the options given below:
$(A)$ Final temperature of the system will be $0^{\circ}C$.
$(B)$ Final temperature of the system will be greater than $0^{\circ}C$.
$(C)$ The final system will have a mixture of ice and water in the ratio of $5:1$.
$(D)$ The final system will have a mixture of ice and water in the ratio of $1:5$.
$(E)$ The final system will have water only.
Choose the correct answer from the options given below:
DifficultJEE MAIN 2023
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