What determines the hardness of the X-rays ob | vedclass

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(D) The hardness of $X-$rays refers to their penetrating power,which is directly related to their energy. According to the Duane-Hunt law,the maximum

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Potential difference between cathode and target

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(D) The hardness of $X-$rays refers to their penetrating power,which is directly related to their energy. According to the Duane-Hunt law,the maximum frequency $f_{max}$ of $X-$rays produced is given by $hf_{max} = eV$,where $e$ is the elementary charge and $V$ is the accelerating potential difference between the cathode and the target. Since $E = hf$,higher potential difference $V$ results in higher energy $X-$rays,which are termed 'hard' $X-$rays. Therefore,the potential difference between the cathode and the target determines the hardness of the $X-$rays.

What determines the hardness of the $X-$rays obtained from the Coolidge tube?

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