What is A in the following reaction?C_6H_5-CH | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The reaction is the electrophilic addition of $HCl$ to allylbenzene $(C_6H_5-CH_2-CH=CH_2)$.According to Markovnikov's rule,the electrophile $(H^+

Vedclass · Accepted Answer

Vedclass · Answer

(D) The reaction is the electrophilic addition of $HCl$ to allylbenzene $(C_6H_5-CH_2-CH=CH_2)$.According to Markovnikov's rule,the electrophile $(H^+)$ adds to the carbon atom of the double bond that has more hydrogen atoms.In allylbenzene,the double bond is between $C_2$ and $C_3$ (where $C_1$ is attached to the phenyl ring: $C_6H_5-CH_2-CH=CH_2$).$H^+$ adds to the terminal $CH_2$ group,forming a stable benzylic carbocation intermediate $(C_6H_5-CH_2-CH^+-CH_3)$.Then,the nucleophile $(Cl^-)$ attacks this carbocation to form the final product: $C_6H_5-CH_2-CHCl-CH_3$ ($1$-phenyl$-2-$chloropropane).Therefore,the correct option is $D$.

What is $A$ in the following reaction?
$C_6H_5-CH_2-CH=CH_2 + HCl \rightarrow A$

Similar Questions

What product is formed when $Br_2$ is added to ethylene in the presence of aqueous $NaCl$?

Addition of $HBr$ to propene yields $2-$bromopropane,while in the presence of benzoyl peroxide,the same reaction yields $1-$bromopropane. Explain and give the mechanism.

The ozonolysis products of an olefin are $CHO-CHO$ and $CHO-CH_2-CH_2-CHO$. The olefin is:

An alkene on ozonolysis gives methanal as one of the products. Its structure is

Product $(A)$ will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module

What is $A$ in the following reaction?$C_6H_5-CH_2-CH=CH_2 + HCl \rightarrow A$