What is X in the following reaction? | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The given reaction shows that $C_6H_{10}$ (cyclohexene) reacts with $KMnO_4-H_2SO_4$ to form adipic acid (hexanedioic acid),which is a standard ox

Vedclass · Accepted Answer

$3-$bromocyclohex$-1-$ene

Vedclass · Answer

(A) The given reaction shows that $C_6H_{10}$ (cyclohexene) reacts with $KMnO_4-H_2SO_4$ to form adipic acid (hexanedioic acid),which is a standard oxidative cleavage reaction of cyclohexene. When cyclohexene $(C_6H_{10})$ reacts with $Br_2$ in the presence of $UV$ light,it undergoes allylic bromination. The allylic position in cyclohexene is the carbon adjacent to the double bond. Therefore,the product $X$ is $3$-bromocyclohex-$1$-ene.

What is $X$ in the following reaction?

Similar Questions

The major product of the reaction is:

Indicate the organic structure for the product expected when $2-$methylpropene is heated with acetyl chloride in the presence of anhydrous zinc chloride.

The addition of $HI$ in the presence of peroxide catalyst does not follow anti-Markovnikov's rule because

Addition of $Br_2$ to $trans-2-butene$ would give a product which is

$2-$hexene $\xrightarrow[(i) O_3]{(ii) H_2O}$ Products
The two products formed in the above reaction are -

Vedclass Test Series

Exam Paper Generator

Online Exam Module