What is Hinsberg reagent?
Benzenesulphonyl chloride $(C_{6}H_{5}SO_{2}Cl)$ is known as Hinsberg's reagent.
It is used to distinguish between primary,secondary,and tertiary amines.
Primary amines react with Hinsberg's reagent to form $N$-alkylbenzenesulphonamide,which is soluble in alkali.
Secondary amines react with Hinsberg's reagent to form $N,N$-dialkylbenzenesulphonamide,which is insoluble in alkali.
Tertiary amines do not react with Hinsberg's reagent.
The reaction of diethylamine (a secondary amine) with benzenesulphonyl chloride is shown below:
$C_{6}H_{5}SO_{2}Cl + HN(C_{2}H_{5})_{2} \rightarrow C_{6}H_{5}SO_{2}N(C_{2}H_{5})_{2} + HCl$
It is used to distinguish between primary,secondary,and tertiary amines.
Primary amines react with Hinsberg's reagent to form $N$-alkylbenzenesulphonamide,which is soluble in alkali.
Secondary amines react with Hinsberg's reagent to form $N,N$-dialkylbenzenesulphonamide,which is insoluble in alkali.
Tertiary amines do not react with Hinsberg's reagent.
The reaction of diethylamine (a secondary amine) with benzenesulphonyl chloride is shown below:
$C_{6}H_{5}SO_{2}Cl + HN(C_{2}H_{5})_{2} \rightarrow C_{6}H_{5}SO_{2}N(C_{2}H_{5})_{2} + HCl$
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Similar Questions
Describe a method for the identification of primary,secondary and tertiary amines. Also write chemical equations of the reactions involved.
Difficult
View SolutionAn organic compound $A$ on treatment with benzene sulphonyl chloride gives compound $B$. $B$ is soluble in dil. $NaOH$ solution. Compound $A$ is:
Which of the following does $NOT$ give carbylamine test?
Given below are two statements:
Statement $I$: All the following compounds react with $p$-toluenesulfonyl chloride:
$C_6H_5NH_2$
$(C_6H_5)_2NH$
$(C_6H_5)_3N$
Statement $II$: Their products in the above reaction are soluble in aqueous $NaOH$.
In the light of the above statements,choose the correct answer from the options given below.
Statement $I$: All the following compounds react with $p$-toluenesulfonyl chloride:
$C_6H_5NH_2$
$(C_6H_5)_2NH$
$(C_6H_5)_3N$
Statement $II$: Their products in the above reaction are soluble in aqueous $NaOH$.
In the light of the above statements,choose the correct answer from the options given below.
How many of the following amine compounds form a product with Hinsberg's reagent $(C_6H_5SO_2Cl)$ that is soluble in $NaOH$?
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