What is the difference in the oxidation numbe | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Step $1$: Calculate the oxidation number of nitrogen in nitric acid $(HNO_3)$. Let the oxidation number of $N$ be $x$. Then, $1 + x + 3(-2) = 0$,

Vedclass · Accepted Answer

+$4$

Vedclass · Answer

(C) Step $1$: Calculate the oxidation number of nitrogen in nitric acid $(HNO_3)$. Let the oxidation number of $N$ be $x$. Then, $1 + x + 3(-2) = 0$, which gives $x - 5 = 0$, so $x = +5$.Step $2$: Calculate the oxidation number of nitrogen in nitrous oxide $(N_2O)$. Let the oxidation number of $N$ be $y$. Then, $2y + (-2) = 0$, which gives $2y = 2$, so $y = +1$.Step $3$: Calculate the difference in oxidation numbers: $+5 - (+1) = +4$.

What is the difference in the oxidation number of nitrogen when nitric acid is converted into nitrous oxide?

Similar Questions

Oxidation number of $Mn$ in $K_2MnO_4$ and $MnSO_4$ are respectively

The difference between the oxidation numbers of the two types of sulphur atoms in $Na_2S_4O_6$ is:

One mole of $N_2H_4$ loses $10 \ moles$ of electrons to form a new compound $Z$. Assuming that all the nitrogen atoms appear in the new compound, what is the oxidation state of nitrogen in $Z$? (There is no change in the oxidation state of hydrogen.)

What are the oxidation states of three $Br$ atoms in $Br_3O_8$ molecule?

What are the oxidation numbers of nitrogen in $NH_4NO_3$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module