What is the final temperature of $0.10 \ mol$ monoatomic ideal gas that performs $75 \ cal$ of work adiabatically if the initial temperature is $227 \ ^\circ C$? (Use $R = 2 \ cal \cdot K^{-1} \cdot mol^{-1}$)

The volume of an ideal gas contracts from $10.0 \ L$ to $2.0 \ L$ under an applied pressure of $2.0 \ atm$. During contraction,the system also evolved $900 \ J$ of heat. The change in internal energy (in $J$) involved in the system is $(1 \ L \ atm = 101.3 \ J)$:

$A$ system performs mechanical work equal to $15 \ kJ$ and loses $2 \ kJ$ of heat to the surroundings. What is the change in internal energy of the system (in $kJ$)?

“The mass and energy both are conserved in an isolated system”,is the statement of

In a process,the work done by the system is equal to the change in its internal energy. Then the process will be ...........

One mole of a gas absorbs $200 \ J$ of heat at constant volume. Its temperature increases from $298 \ K$ to $308 \ K$. The change in its internal energy is ....... Joules.