What is the formal charge on the C atom in th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The formula for formal charge is: $	ext{Formal charge} = [ 	ext{Total no. of valence } e^- 	ext{ in free state} ] - [ 	ext{Total no. of lone p

Vedclass · Accepted Answer

Zero

Vedclass · Answer

(D) The formula for formal charge is: $	ext{Formal charge} = [ 	ext{Total no. of valence } e^- 	ext{ in free state} ] - [ 	ext{Total no. of lone pair electrons} ] - \frac{1}{2} [ 	ext{Total no. of bonding electrons} ]$. For the carbon atom $(C)$ in the structure $S \equiv C - \ddot{N} :$,the number of valence electrons is $4$. The carbon atom has $0$ lone pair electrons and forms $4$ bonds (a triple bond with $S$ and a single bond with $N$),which corresponds to $8$ bonding electrons. Substituting these values: $	ext{Formal charge} = 4 - 0 - \frac{1}{2} 	imes 8 = 4 - 4 = 0$.

Column $I$ (Molecules)	Column $II$ (Number of lone pairs on central atom)
$A. \ NH_3$	$1. \ \text{Two}$
$B. \ H_2O$	$2. \ \text{Three}$
$C. \ XeF_2$	$3. \ \text{Zero}$
$D. \ CH_4$	$4. \ \text{Four}$
	$5. \ \text{One}$

What is the formal charge on the $C$ atom in the structure $S \equiv C - \ddot{N} :$?

Similar Questions

Which of the following is a Lewis acid?

The number of $S-S$,$S-O-S$,and $O-H$ linkages in a molecule of pyrosulphurous acid $(H_2S_2O_5)$ are respectively

Which of the following cannot act as a Lewis base?

Select the $CORRECT$ statement.

Vedclass Test Series

Exam Paper Generator

Online Exam Module