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(D) The stability of free radicals is determined by resonance and hyperconjugation. $1$. Resonance stabilized radicals are more stable than alkyl radi

Vedclass · Accepted Answer

$(CH_3)_2\dot{C}H < (CH_3)_3\dot{C} < (C_6H_5)_2\dot{C}H < (C_6H_5)_3\dot{C}$

Vedclass · Answer

(D) The stability of free radicals is determined by resonance and hyperconjugation. $1$. Resonance stabilized radicals are more stable than alkyl radicals. $2$. $(C_6H_5)_3\dot{C}$ (triphenylmethyl radical) is the most stable due to extensive resonance with three phenyl rings. $3$. $(C_6H_5)_2\dot{C}H$ (diphenylmethyl radical) is next in stability due to resonance with two phenyl rings. $4$. Among alkyl radicals,$(CH_3)_3\dot{C}$ (tert-butyl radical) is more stable than $(CH_3)_2\dot{C}H$ (isopropyl radical) due to more hyperconjugation. Thus,the increasing order of stability is: $(CH_3)_2\dot{C}H < (CH_3)_3\dot{C} < (C_6H_5)_2\dot{C}H < (C_6H_5)_3\dot{C}$.

What is the increasing order of stability for the following free radicals?

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