What is the magnetic moment of a divalent ion | vedclass

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(B) The atomic number of the element is $28$, which corresponds to Nickel $(Ni)$.The electronic configuration of $Ni$ $(Z=28)$ is $[Ar] 3d^8 4s^2$.A d

Vedclass · Accepted Answer

$2.84$

Vedclass · Answer

(B) The atomic number of the element is $28$, which corresponds to Nickel $(Ni)$.The electronic configuration of $Ni$ $(Z=28)$ is $[Ar] 3d^8 4s^2$.A divalent ion $(Ni^{2+})$ is formed by the loss of two electrons from the $4s$ orbital, resulting in the configuration $[Ar] 3d^8$.In the $3d^8$ configuration, there are $2$ unpaired electrons $(n=2)$.The magnetic moment $(\mu)$ is calculated using the spin-only formula: $\mu = \sqrt{n(n+2)} \ BM$.Substituting $n=2$: $\mu = \sqrt{2(2+2)} = \sqrt{8} \approx 2.84 \ BM$.

What is the magnetic moment of a divalent ion in aqueous solution if its atomic number is $28$ (in $BM$)?

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