What is the maximum number of emission lines | vedclass

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(B) When the excited electron of an $H$ atom in $n=6$ drops to the ground state,the possible transitions are from $n=6$ to $n=5, 4, 3, 2, 1$; $n=5$ to

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$15$

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(B) When the excited electron of an $H$ atom in $n=6$ drops to the ground state,the possible transitions are from $n=6$ to $n=5, 4, 3, 2, 1$; $n=5$ to $n=4, 3, 2, 1$,and so on.The total number of spectral lines produced when an electron in the $n^{th}$ level drops down to the ground state is given by the formula:$	ext{Number of spectral lines} = \frac{n(n-1)}{2}$Given $n=6$:$	ext{Number of spectral lines} = \frac{6(6-1)}{2} = \frac{6 	imes 5}{2} = 15$Thus,a total of $15$ lines will be obtained in the emission spectrum.

What is the maximum number of emission lines when the excited electron of an $H$ atom in $n=6$ drops to the ground state?

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