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(D) The Wurtz reaction for the preparation of ethane is given by the equation:$2CH_3I + 2Na \xrightarrow{	ext{dry ether}} C_2H_6 + 2NaI$According to

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$284$

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(D) The Wurtz reaction for the preparation of ethane is given by the equation:$2CH_3I + 2Na \xrightarrow{	ext{dry ether}} C_2H_6 + 2NaI$According to the stoichiometry of the reaction,$2$ moles of methyl iodide $(CH_3I)$ are required to produce $1$ mole of ethane $(C_2H_6)$.The molar mass of $CH_3I$ is calculated as: $12 (C) + 3 (H) + 127 (I) = 142 \ g/mol$.Therefore,the mass of $2$ moles of $CH_3I$ required is: $2 	imes 142 \ g = 284 \ g$.

What is the minimum quantity (in grams) of $methyl$ iodide required for preparing one mole of ethane by Wurtz reaction? (Atomic weight of iodine $= 127$)

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