What is the molarity of H_2SO_4 solution havi | vedclass

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(C) The concentration of hydrogen ions is given by $[H^+] = 10^{-pH} = 10^{-4} 	ext{ M}$.Since $H_2SO_4$ is a strong diprotic acid, it dissociates as

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$5 	imes 10^{-5} 	ext{ M}$

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(C) The concentration of hydrogen ions is given by $[H^+] = 10^{-pH} = 10^{-4} 	ext{ M}$.Since $H_2SO_4$ is a strong diprotic acid, it dissociates as $H_2SO_4 ightarrow 2H^+ + SO_4^{2-}$.Therefore, the molarity of the $H_2SO_4$ solution is $[H_2SO_4] = \frac{[H^+]}{2}$.$[H_2SO_4] = \frac{10^{-4}}{2} 	ext{ M} = 0.5 	imes 10^{-4} 	ext{ M} = 5 	imes 10^{-5} 	ext{ M}$.

What is the molarity of $H_2SO_4$ solution having $pH = 4$?

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