What is the number of hydrogen molecules need | vedclass

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(C) The balanced chemical equation for the synthesis of ammonia is: $N_2(g) + 3H_2(g) ightarrow 2NH_3(g)$.From the equation, $3 	ext{ moles}$ of $H

Vedclass · Accepted Answer

$0.18 	imes 10^{24}$

Vedclass · Answer

(C) The balanced chemical equation for the synthesis of ammonia is: $N_2(g) + 3H_2(g) ightarrow 2NH_3(g)$.From the equation, $3 	ext{ moles}$ of $H_2$ produce $2 	ext{ moles}$ of $NH_3$.Molar mass of $NH_3 = 14 + 3 	imes 1 = 17 	ext{ g/mol}$.Moles of $NH_3$ produced $= \frac{3.4 	ext{ g}}{17 	ext{ g/mol}} = 0.2 	ext{ mol}$.Since $2 	ext{ moles}$ of $NH_3$ require $3 	ext{ moles}$ of $H_2$, $0.2 	ext{ moles}$ of $NH_3$ require $\frac{3}{2} 	imes 0.2 = 0.3 	ext{ moles}$ of $H_2$.Number of $H_2$ molecules $= 0.3 	imes 6.022 	imes 10^{23} \approx 1.8 	imes 10^{23} = 0.18 	imes 10^{24}$.

What is the number of hydrogen molecules needed to synthesize $3.4 \text{ g}$ of ammonia by reaction with nitrogen?

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