What is the number of photons of light with a wavelength of $4000 \ pm$ that provide $1 \ J$ of energy?

(N/A) Energy $(E)$ of a single photon is given by $E = \frac{hc}{\lambda}$.
For $n$ photons, the total energy $(E_n)$ is $E_n = \frac{n \times hc}{\lambda}$.
Rearranging for $n$, we get $n = \frac{E_n \times \lambda}{hc}$.
Given values:
$E_n = 1 \ J$
$\lambda = 4000 \ pm = 4000 \times 10^{-12} \ m = 4 \times 10^{-9} \ m$
$h = 6.626 \times 10^{-34} \ J \cdot s$
$c = 3 \times 10^8 \ m/s$
Substituting these values:
$n = \frac{1 \times 4 \times 10^{-9}}{6.626 \times 10^{-34} \times 3 \times 10^8}$
$n = \frac{4 \times 10^{-9}}{19.878 \times 10^{-26}}$
$n \approx 2.012 \times 10^{16}$.
Thus, the number of photons is $2.012 \times 10^{16}$.