What is the oxidation number of phosphorus in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The chemical formula for calcium phosphate is $Ca_3(PO_4)_2$.Let the oxidation number of phosphorus be $x$.The oxidation number of calcium $(Ca)$

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(C) The chemical formula for calcium phosphate is $Ca_3(PO_4)_2$.Let the oxidation number of phosphorus be $x$.The oxidation number of calcium $(Ca)$ is $+2$ and oxygen $(O)$ is $-2$.For the neutral compound $Ca_3(PO_4)_2$,the sum of oxidation numbers must be zero:$3(+2) + 2[x + 4(-2)] = 0$$6 + 2[x - 8] = 0$$6 + 2x - 16 = 0$$2x - 10 = 0$$2x = 10$$x = +5$Therefore,the oxidation number of phosphorus is $+5$.

What is the oxidation number of phosphorus in calcium phosphate?

Similar Questions

$A$ compound contains atoms $X$,$Y$,and $Z$. The oxidation number of $X$ is $+2$,$Y$ is $+5$ and $Z$ is $-2$. Therefore,a possible formula of the compound is

The oxidation number of chlorine in $HOCl$ is:

Oxidation numbers of $P$ in $PO_4^{3-}$,$S$ in $SO_4^{2-}$ and that of $Cr$ in $Cr_2O_7^{2-}$ are respectively

The correct order of $N$ compounds in their decreasing order of oxidation states is:

In thiosulphuric acid $(H_2S_2O_3)$,which of the following statements is correct?

Vedclass Test Series

Exam Paper Generator

Online Exam Module