What is the percent by mass of titanium in ru | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In the rutile structure,oxide ions form a closest-packed array. If there are $N$ oxide ions,the number of octahedral holes is $N$. Since titanium

Vedclass · Accepted Answer

$ \simeq 60\%, +4 $

Vedclass · Answer

(C) In the rutile structure,oxide ions form a closest-packed array. If there are $N$ oxide ions,the number of octahedral holes is $N$. Since titanium occupies one-half of the octahedral holes,the number of $Ti$ atoms is $N/2$. The ratio of $Ti:O$ is $(N/2):N = 1:2$. Thus,the formula of the mineral is $TiO_2$. The oxidation number of $Ti$ in $TiO_2$ is calculated as $x + 2(-2) = 0$,so $x = +4$. The molar mass of $TiO_2 = 48 + 2(16) = 80 	ext{ g/mol}$. The percentage by mass of $Ti = (48 / 80) 	imes 100 = 60\% $.

List-$I$	List-$II$
$A$. $ABCABC...$ layers	$I$. $F$-centres
$B$. Thermodynamics defects	$II$. $X$-ray diffraction
$C$. $Farbenzenter$	$III$. Vacancy defects
$D$. $Debye-Scherrer$ method	$IV$. Semiconductors
	$V$. Silver

What is the percent by mass of titanium in rutile,a mineral that contains titanium and oxygen,if the structure can be described as a closest-packed array of oxide ions,with titanium in one half of the octahedral holes? What is the oxidation number of titanium? $(Ti = 48, O = 16)$

Similar Questions

In the given cooling curve,what is the crystallization temperature in $K$?

Match the following:
List-$I$ List-$II$
$A$. $ABCABC...$ layers $I$. $F$-centres
$B$. Thermodynamics defects $II$. $X$-ray diffraction
$C$. $Farbenzenter$ $III$. Vacancy defects
$D$. $Debye-Scherrer$ method $IV$. Semiconductors
$V$. Silver

The halide of a metal $MX$ crystallizes in a $ccp$ structure ($NaCl$ type). If all the atoms situated at one of the tetrad axes are removed,what will be the simplest molecular formula of the halide?

Calculate the number of atoms present in $1.58 \ g$ of a metal that forms a $bcc$ structure,given that $\varrho \times a^3 = 1.58 \times 10^{-22} \ g$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module