What is the ratio between the distance travel | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In one time period $(T)$,an oscillator performing Simple Harmonic Motion $(SHM)$ moves from the mean position to the extreme position $(+A)$,then

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(C) In one time period $(T)$,an oscillator performing Simple Harmonic Motion $(SHM)$ moves from the mean position to the extreme position $(+A)$,then back to the mean position,then to the other extreme position $(-A)$,and finally returns to the mean position.The total distance travelled $(d)$ is the sum of the magnitudes of these displacements:$d = |+A| + |-A| + |-A| + |+A| = 4A$Here,$A$ is the amplitude of the oscillation.The ratio of the distance travelled $(d)$ to the amplitude $(A)$ is:$	ext{Ratio} = \frac{d}{A} = \frac{4A}{A} = 4$

What is the ratio between the distance travelled by the oscillator in one time period and the amplitude?

Similar Questions

In simple harmonic motion,the acceleration of a particle is given by $a = -bx$. What is the time period of the motion?

Explain periodic function.

What is periodic motion? Give its examples.

Consider a one-dimensional potential $V(x)$ as shown in the figure below. $A$ classical particle of mass $m$ moves under its influence and has total energy $E$ as shown below. The motion is

The function $\sin^2(\omega t)$ represents:

Vedclass Test Series

Exam Paper Generator

Online Exam Module