What is the relationship between the average | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The expressions for the velocities are as follows: Most probable velocity $(\alpha) = \sqrt{\frac{2RT}{M}}$ Average velocity $(v) = \sqrt{\frac{8R

Vedclass · Accepted Answer

$\alpha : v : u :: 1 : 1.128 : 1.224$

Vedclass · Answer

(A) The expressions for the velocities are as follows: Most probable velocity $(\alpha) = \sqrt{\frac{2RT}{M}}$ Average velocity $(v) = \sqrt{\frac{8RT}{\pi M}}$ Root mean square velocity $(u) = \sqrt{\frac{3RT}{M}}$ Taking the ratio $\alpha : v : u$: $\sqrt{2} : \sqrt{\frac{8}{\pi}} : \sqrt{3}$ Dividing by $\sqrt{2} \approx 1.414$: $1 : \sqrt{\frac{4}{\pi}} : \sqrt{1.5}$ $1 : 1.128 : 1.224$

What is the relationship between the average velocity $(v)$,root mean square velocity $(u)$,and most probable velocity $(\alpha)$?

Similar Questions

Which of the following has maximum root mean square velocity at the same temperature?

$A$ $50 \, L$ container holds $0.5 \, mol$ of $O_2$ gas at $27 \, ^oC$ and $2 \, atm$ pressure. If half of the $O_2$ molecules are removed from the container,what happens to the $rms$ speed of the $O_2$ molecules?

If the average velocity of $N_2$ gas at $27 \, ^oC$ is $0.3 \, m/sec$,then at what temperature in $K$ will the average velocity be $0.6 \, m/sec$?

Predict the correct order of rate of diffusion of the following molecules.

The root mean square speed of $O_2$ at $STP$ is ........ $cm/s$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module