What is the value of escape velocity of a bod | vedclass

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(A) The escape velocity $v_e$ of a body from the surface of a planet is given by the formula $v_e = \sqrt{\frac{2GM}{R}}$,where $G$ is the gravitation

Vedclass · Accepted Answer

Earth: $11.2 	ext{ km/s}$,Moon: $2.38 	ext{ km/s}$

Vedclass · Answer

(A) The escape velocity $v_e$ of a body from the surface of a planet is given by the formula $v_e = \sqrt{\frac{2GM}{R}}$,where $G$ is the gravitational constant,$M$ is the mass of the planet,and $R$ is its radius.For Earth,the mass $M_e \approx 5.97 	imes 10^{24} 	ext{ kg}$ and radius $R_e \approx 6.37 	imes 10^6 	ext{ m}$. Substituting these values,we get $v_e \approx 11.2 	ext{ km/s}$.For the Moon,the mass $M_m \approx 7.35 	imes 10^{22} 	ext{ kg}$ and radius $R_m \approx 1.74 	imes 10^6 	ext{ m}$. Substituting these values,we get $v_e \approx 2.38 	ext{ km/s}$.

What is the value of escape velocity of a body lying on the surface of Earth and Moon?

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