What is the value of the rate constant of a first-order reaction if the slope of the graph between $\log_{10} \frac{[A]_0}{[A]_t}$ ($y$-axis) and time ($x$-axis) is $1 \times 10^{-3}$?
- A$4.34 \times 10^{-3}$
- B$6.93 \times 10^{-3}$
- C$2.303 \times 10^{-3}$
- D$5.12 \times 10^{-3}$
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Similar Questions
The following data were obtained during the first order thermal decomposition of $N_{2}O_{5(g)}$ at constant volume:
$2N_{2}O_{5(g)} \rightarrow 2N_{2}O_{4(g)} + O_{2(g)}$
$S.No.$ Time $/$ $s$ Total pressure $/$ $atm$ $1.$ $0$ $0.5$ $2.$ $100$ $0.512$
Calculate the rate constant.
$2N_{2}O_{5(g)} \rightarrow 2N_{2}O_{4(g)} + O_{2(g)}$
| $S.No.$ | Time $/$ $s$ | Total pressure $/$ $atm$ |
| $1.$ | $0$ | $0.5$ |
| $2.$ | $100$ | $0.512$ |
Calculate the rate constant.
Difficult
View SolutionFor the first order reaction with rate constant $k$,which expression gives the half-life period? (Initial concentration $= a$)
Easy
View SolutionAn organic compound undergoes first-order decomposition. The time taken for its decomposition to $1/8$ and $1/10$ of its initial concentration are $t_{1/8}$ and $t_{1/10}$ respectively. What is the value of $\frac{t_{1/8}}{t_{1/10}} \times 10$? (Given: $\log_{10} 2 = 0.3$)
What is the value of the slope when a graph is plotted of $\log \frac{[R]_0}{[R]}$ versus $t$ (time) for a first-order reaction?
$A$ first order reaction is $60 \%$ complete in $20 \ min$. How long will the reaction take to be $84 \%$ complete (in $min$)?
MediumKCET 2012
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