What is the value of the spin-only magnetic m | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The electronic configuration of $Ni$ $(Z=28)$ is $[Ar] 3d^8 4s^2$. For $Ni^{2+}$,the configuration is $[Ar] 3d^8$. In the $3d$ subshell,there are

Vedclass · Accepted Answer

$2.8$

Vedclass · Answer

(C) The electronic configuration of $Ni$ $(Z=28)$ is $[Ar] 3d^8 4s^2$. For $Ni^{2+}$,the configuration is $[Ar] 3d^8$. In the $3d$ subshell,there are $8$ electrons,which results in $2$ unpaired electrons $(n=2)$. The spin-only magnetic moment is calculated using the formula $\mu = \sqrt{n(n+2)} \ BM$. Substituting $n=2$: $\mu = \sqrt{2(2+2)} = \sqrt{2 	imes 4} = \sqrt{8} \approx 2.83 \ BM$. Thus,the value is approximately $2.8 \ BM$.

What is the value of the spin-only magnetic moment of $Ni$ $(Z=28)$ in the $+2$ oxidation state (in $BM$)?

Similar Questions

The correct order of decreasing third ionisation enthalpy of $Ti$,$V$,$Cr$,and $Mn$ is:

The $3d-$ elements show variable oxidation states. What is the maximum oxidation state shown by the element $Mn$?

Why are $Mn^{2+}$ compounds more stable than $Fe^{2+}$ towards oxidation to their $+3$ state?

Compare the stability of the $+2$ oxidation state for the elements of the first transition series.

Identify the incorrect statement in the following.

Vedclass Test Series

Exam Paper Generator

Online Exam Module