What is the value of frac{2.75 times 2.75 tim | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let $a = 2.75$ and $b = 2.25$.The given expression is of the form $\frac{a^3 - b^3}{a^2 + ab + b^2}$.We know the algebraic identity: $a^3 - b^3 =

Vedclass · Accepted Answer

$\frac{1}{2}$

Vedclass · Answer

(B) Let $a = 2.75$ and $b = 2.25$.The given expression is of the form $\frac{a^3 - b^3}{a^2 + ab + b^2}$.We know the algebraic identity: $a^3 - b^3 = (a - b)(a^2 + ab + b^2)$.Substituting this into the expression,we get:$\frac{(a - b)(a^2 + ab + b^2)}{a^2 + ab + b^2} = a - b$.Now,substitute the values of $a$ and $b$ back:$2.75 - 2.25 = 0.5$.Since $0.5 = \frac{1}{2}$,the correct option is $B$.

What is the value of $\frac{2.75 \times 2.75 \times 2.75 - 2.25 \times 2.25 \times 2.25}{2.75 \times 2.75 + 2.75 \times 2.25 + 2.25 \times 2.25}$?

Similar Questions

If $x+\frac{2}{3+\frac{4}{5+\frac{7}{6}}}=10$,then the value of $x$ is

If $a+b+c=0,$ then the value of $\frac{a^{2}+b^{2}+c^{2}}{a^{2}-b c}$ is

What will come in the place of the question mark $(?)$ in the following expression?
$\sqrt{15^{2} \times 12 \div 9 - 125 + 21} = ?$

$A$ sum of $Rs. 1360$ has been divided among $A, B$ and $C$ such that $A$ gets $\frac{2}{3}$ of what $B$ gets and $B$ gets $\frac{1}{4}$ of what $C$ gets. $B$'s share is (in $Rs.$)

$12 \frac{5}{7} + 23 \frac{3}{5} - 14 \frac{1}{3} = 28 \frac{4}{7} - ?$

Vedclass Test Series

Exam Paper Generator

Online Exam Module