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(B) In the complex $[Ni(CN)_4]^{2-}$,the central metal ion is $Ni^{2+}$.The atomic number of $Ni$ is $28$,so the electronic configuration of $Ni^{2+}$

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$dsp^2$

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(B) In the complex $[Ni(CN)_4]^{2-}$,the central metal ion is $Ni^{2+}$.The atomic number of $Ni$ is $28$,so the electronic configuration of $Ni^{2+}$ is $[Ar] 3d^8$.$CN^-$ is a strong field ligand,which causes pairing of electrons in the $3d$ orbitals.This results in one empty $3d$ orbital,one $4s$ orbital,and two $4p$ orbitals being available for hybridisation.Thus,the hybridisation involved is $dsp^2$,which corresponds to a square planar geometry.

What type of hybridisation is present in square planar geometry of complex $[Ni(CN)_4]^{2-}$?

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