What will be the molar specific heat at const | vedclass

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(B) For a gas at temperature $T$, the internal energy is given by:$U = \frac{f}{2} \mu R T$where $f$ is the degree of freedom.The change in internal e

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$\frac{5}{2} R$

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(B) For a gas at temperature $T$, the internal energy is given by:$U = \frac{f}{2} \mu R T$where $f$ is the degree of freedom.The change in internal energy is:$\Delta U = \frac{f}{2} \mu R \Delta T$For a process at constant volume, the heat supplied is equal to the change in internal energy:$\Delta Q_V = \mu C_V \Delta T = \Delta U$Equating the two expressions for $\Delta U$:$\mu C_V \Delta T = \frac{f}{2} \mu R \Delta T$$C_V = \frac{f}{2} R$For rigid diatomic molecules, the degree of freedom $f = 5$ ($3$ translational + $2$ rotational).Substituting $f = 5$ into the formula:$C_V = \frac{5}{2} R$

What will be the molar specific heat at constant volume of an ideal gas consisting of rigid diatomic molecules?

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