What will be the theoretical value of magneti | vedclass

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(D) The electronic configuration of $Fe$ $(Z=26)$ is $[Ar] 3d^6 4s^2$.For $Fe^{3+}$,the configuration is $[Ar] 3d^5$.$CN^-$ is a strong field ligand,w

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$1.73$

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(D) The electronic configuration of $Fe$ $(Z=26)$ is $[Ar] 3d^6 4s^2$.For $Fe^{3+}$,the configuration is $[Ar] 3d^5$.$CN^-$ is a strong field ligand,which causes pairing of electrons in the $3d$ orbitals.In $Fe^{3+}$ $(3d^5)$,the five electrons are paired such that four electrons form two pairs and one electron remains unpaired $(n=1)$.The magnetic moment $(\mu)$ is calculated using the formula $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons.$\mu = \sqrt{1(1+2)} = \sqrt{3} \approx 1.73 \ BM$.

List-$I$	List-$II$
$(a).$ $[Co(NH_3)_6][Cr(CN)_6]$	$(i).$ Linkage isomerism
$(b).$ $[Co(NH_3)_3(NO_2)_3]$	$(ii).$ Solvate isomerism
$(c).$ $[Cr(H_2O)_6]Cl_3$	$(iii).$ Coordination isomerism
$(d).$ $cis-[CrCl_2(ox)_2]^{3-}$	$(iv).$ Optical isomerism

What will be the theoretical value of magnetic moment $(\mu)$ when $CN^-$ ligands join $Fe^{3+}$ ion to yield a complex (in $BM$)?

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