What will be the weight of lime (CaO) obtaine | vedclass

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(D) The chemical reaction for the decomposition of limestone is: $CaCO_3(s) \longrightarrow CaO(s) + CO_2(g)$Mass of pure $CaCO_3 = 300 \ kg 	imes 0.

Vedclass · Accepted Answer

$151.2$

Vedclass · Answer

(D) The chemical reaction for the decomposition of limestone is: $CaCO_3(s) \longrightarrow CaO(s) + CO_2(g)$Mass of pure $CaCO_3 = 300 \ kg 	imes 0.90 = 270 \ kg = 270,000 \ g$.Molar mass of $CaCO_3 = 40 + 12 + (3 	imes 16) = 100 \ g/mol$.Moles of $CaCO_3 = \frac{270,000 \ g}{100 \ g/mol} = 2700 \ mol$.According to the stoichiometry,$1 \ mol$ of $CaCO_3$ produces $1 \ mol$ of $CaO$.Therefore,$2700 \ mol$ of $CaCO_3$ produces $2700 \ mol$ of $CaO$.Molar mass of $CaO = 40 + 16 = 56 \ g/mol$.Weight of $CaO = 2700 \ mol 	imes 56 \ g/mol = 151,200 \ g = 151.2 \ kg$.

What will be the weight of lime $(CaO)$ obtained by heating $300 \ kg$ of $90\%$ pure limestone $(CaCO_3)$?

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