What would be the cost of laying a carpet on | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let the length of the floor be $32x$ and the breadth be $21x$.Given that the perimeter of the floor is $212$ feet.The formula for the perimeter of

Vedclass · Accepted Answer

$6720$

Vedclass · Answer

(A) Let the length of the floor be $32x$ and the breadth be $21x$.Given that the perimeter of the floor is $212$ feet.The formula for the perimeter of a rectangle is $2 	imes (	ext{length} + 	ext{breadth})$.So,$2(32x + 21x) = 212$.$2(53x) = 212$.$106x = 212$.$x = 2$.Therefore,length $= 32 	imes 2 = 64$ feet and breadth $= 21 	imes 2 = 42$ feet.The area of the floor is $	ext{length} 	imes 	ext{breadth} = 64 	imes 42 = 2688$ square feet.The cost of laying the carpet is $	ext{Area} 	imes 	ext{cost per square foot} = 2688 	imes 2.5 = ₹ 6720$.

What would be the cost of laying a carpet on a floor which has its length and breadth in the respective ratio of $32:21$ and where its perimeter is $212$ feet,if the cost per square foot of laying the carpet is $₹ 2.5$?

Similar Questions

In a triangle $ABC$,$AB + BC = 12 \text{ cm}$,$BC + CA = 14 \text{ cm}$,and $CA + AB = 18 \text{ cm}$. Find the radius of the circle (in $\text{cm}$) which has the same perimeter as the triangle.

The radius and vertical height of a cone are $5 \text{ cm}$ and $12 \text{ cm}$ respectively. Then its lateral surface area is? (in $\text{cm}^2$)

Three equal cubes are placed adjacently in a row. Find the ratio of the total surface area of the new cuboid to the sum of the surface areas of the three cubes.

The area of the circle inscribed in an equilateral triangle of side $24 \, cm$ is

What is the radius of a circle,to the nearest $cm$,whose area is equal to the sum of the areas of the three circles of radii $22\, cm$,$19\, cm$,and $8\, cm$ respectively? (in $cm$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module