What would be the ratio of the root mean squa | vedclass

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(A) The root mean square velocity $(u_{rms})$ is given by the formula $u_{rms} = \sqrt{\frac{3RT}{M}}$.For hydrogen $(H_2)$ at $T_1 = 50 \ K$ and mola

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$1/1$

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(A) The root mean square velocity $(u_{rms})$ is given by the formula $u_{rms} = \sqrt{\frac{3RT}{M}}$.For hydrogen $(H_2)$ at $T_1 = 50 \ K$ and molar mass $M_1 = 2 \ g/mol$:$u_{H_2} = \sqrt{\frac{3R(50)}{2}}$.For oxygen $(O_2)$ at $T_2 = 800 \ K$ and molar mass $M_2 = 32 \ g/mol$:$u_{O_2} = \sqrt{\frac{3R(800)}{32}}$.The ratio is $\frac{u_{H_2}}{u_{O_2}} = \sqrt{\frac{50}{2} 	imes \frac{32}{800}} = \sqrt{25 	imes \frac{1}{25}} = \sqrt{1} = 1/1$.

What would be the ratio of the root mean square velocity of hydrogen gas at $50 \ K$ and that of oxygen at $800 \ K$?

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