When SO_2 is passed through an acidic solutio | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The balanced chemical equation for the reaction is:$K_2Cr_2O_7 + 3SO_2 + H_2SO_4 \rightarrow K_2SO_4 + Cr_2(SO_4)_3 + H_2O$In $K_2Cr_2O_7$,the oxi

Vedclass · Accepted Answer

$+6$ to $+3$

Vedclass · Answer

(C) The balanced chemical equation for the reaction is:$K_2Cr_2O_7 + 3SO_2 + H_2SO_4 \rightarrow K_2SO_4 + Cr_2(SO_4)_3 + H_2O$In $K_2Cr_2O_7$,the oxidation state of chromium $(Cr)$ is calculated as:$2(+1) + 2(x) + 7(-2) = 0$ $\Rightarrow 2 + 2x - 14 = 0$ $\Rightarrow 2x = 12$ $\Rightarrow x = +6$In $Cr_2(SO_4)_3$,the oxidation state of chromium $(Cr)$ is $+3$ because the sulphate ion $(SO_4^{2-})$ has a charge of $-2$.Thus,the oxidation state of chromium changes from $+6$ to $+3$.

When $SO_2$ is passed through an acidic solution of potassium dichromate,chromium sulphate is formed. What is the change in the oxidation state of chromium?

Similar Questions

In which compound is the oxidation state of nitrogen $+1$?

In which of the following compounds is the maximum oxidation state of the central atom present?

$2$ mole of $N_2H_4$ loses $16$ mole of electrons and is converted to a new compound $X$. Assuming that all of the $N$ atoms appear in the new compound,what is the oxidation state of $N$ in $X$?

What is the oxidation number of oxygen in a superoxide ion?

$A$ compound contains $x$,$y$,and $z$ atoms. The oxidation number of $x$ is $+3$,$y$ is $-5$,and $z$ is $+1$. The possible formula of the compound is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module