In which of the following compounds is the ma | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To find the oxidation state of the central atom:$1$. In $CrO_2Cl_2$: $x + 2(-2) + 2(-1) = 0 \implies x = +6$.$2$. In $MnO_4^-$: $x + 4(-2) = -1 \i

Vedclass · Accepted Answer

$CrO_2Cl_2$ and $MnO_4^-$

Vedclass · Answer

(A) To find the oxidation state of the central atom:$1$. In $CrO_2Cl_2$: $x + 2(-2) + 2(-1) = 0 \implies x = +6$.$2$. In $MnO_4^-$: $x + 4(-2) = -1 \implies x = +7$.$3$. In $MnO_2$: $x + 2(-2) = 0 \implies x = +4$.$4$. In $[Fe(CN)_6]^{3-}$: $x + 6(-1) = -3 \implies x = +3$.$5$. In $[Co(CN)_6]^{3-}$: $x + 6(-1) = -3 \implies x = +3$.$6$. In $MnO$: $x + (-2) = 0 \implies x = +2$.The maximum oxidation state is $+7$ in $MnO_4^-$,which is present in option $A$.

In which of the following compounds is the maximum oxidation state of the central atom present?

Similar Questions

Calculate the consecutive oxidation numbers of $Br$ in $Br_3O_8$.

What is the oxidation number of sulfur in $H_2S_2O_8$?

In $NH_4NO_2$,the oxidation number of nitrogen will be

Oxidation number of oxygen in ozone $(O_3)$ is

The oxidation number of carbon in $CH_3Cl$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module