When (5k+1)^2 is divided by 5,the remainder i | vedclass

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(B) We are given the expression $(5k+1)^2$.Expanding this using the identity $(a+b)^2 = a^2 + 2ab + b^2$,we get:$(5k+1)^2 = (5k)^2 + 2(5k)(1) + (1)^2$

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(B) We are given the expression $(5k+1)^2$.Expanding this using the identity $(a+b)^2 = a^2 + 2ab + b^2$,we get:$(5k+1)^2 = (5k)^2 + 2(5k)(1) + (1)^2$$= 25k^2 + 10k + 1$$= 5(5k^2 + 2k) + 1$Here,the expression is in the form $5q + 1$,where $q = 5k^2 + 2k$ is an integer.Therefore,when $(5k+1)^2$ is divided by $5$,the remainder is $1$.

When $(5k+1)^2$ is divided by $5$,the remainder is . . . . . . .

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