When O_{2} is converted into O_{2}^{+},what h | vedclass

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(D) The molecular orbital configuration of $O_{2}$ is $(\sigma 1s)^{2}(\sigma^{*} 1s)^{2}(\sigma 2s)^{2}(\sigma^{*} 2s)^{2}(\sigma 2p_{z})^{2}(\pi 2p_

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Paramagnetic character decreases and the bond order increases

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(D) The molecular orbital configuration of $O_{2}$ is $(\sigma 1s)^{2}(\sigma^{*} 1s)^{2}(\sigma 2s)^{2}(\sigma^{*} 2s)^{2}(\sigma 2p_{z})^{2}(\pi 2p_{x})^{2}(\pi 2p_{y})^{2}(\pi^{*} 2p_{x})^{1}(\pi^{*} 2p_{y})^{1}$.Bond order $= \frac{N_{b} - N_{a}}{2} = \frac{10 - 6}{2} = 2$. It has $2$ unpaired electrons.For $O_{2}^{+}$,the configuration is $(\sigma 1s)^{2}(\sigma^{*} 1s)^{2}(\sigma 2s)^{2}(\sigma^{*} 2s)^{2}(\sigma 2p_{z})^{2}(\pi 2p_{x})^{2}(\pi 2p_{y})^{2}(\pi^{*} 2p_{x})^{1}$.Bond order $= \frac{10 - 5}{2} = 2.5$. It has $1$ unpaired electron.Thus,when $O_{2}$ is converted into $O_{2}^{+}$,the paramagnetic character decreases and the bond order increases.

When $O_{2}$ is converted into $O_{2}^{+}$,what happens to its paramagnetic character and bond order?

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