When $22.4 \ L$ of $H_{2(g)}$ is mixed with $11.2 \ L$ of $Cl_{2(g)}$,each at $S.T.P.$,the moles of $HCl_{(g)}$ formed is equal to

  • A
    $1 \ mol$ of $HCl_{(g)}$
  • B
    $2 \ mol$ of $HCl_{(g)}$
  • C
    $0.5 \ mol$ of $HCl_{(g)}$
  • D
    $1.5 \ mol$ of $HCl_{(g)}$

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