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(D) In the Krebs cycle (Tricarboxylic Acid cycle),$1$ molecule of pyruvic acid is first converted into Acetyl-CoA. However,the question specifically a

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$3, 5, 2$

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(D) In the Krebs cycle (Tricarboxylic Acid cycle),$1$ molecule of pyruvic acid is first converted into Acetyl-CoA. However,the question specifically asks for the products released during the cycle itself per molecule of pyruvic acid.$1$. Decarboxylation occurs at $2$ steps in the Krebs cycle,but if we consider the complete oxidation of $1$ pyruvate (including the link reaction),$3$ molecules of $CO_2$ are released.$2$. Dehydrogenation (release of $2H^+$ and $2e^-$) occurs at $3$ stages in the Krebs cycle (Isocitrate to $\alpha$-ketoglutarate,$\alpha$-ketoglutarate to Succinyl-CoA,and Malate to Oxaloacetate).$3$. Therefore,for $1$ molecule of pyruvic acid,$a = 3$ ($CO_2$ molecules),$b = 3$ (stages of dehydrogenation),and $c = 2$ (electrons per dehydrogenation step). Thus,the correct sequence is $3, 3, 2$.

When $1$ molecule of pyruvic acid passes through the process of the Krebs cycle,$a$ molecules of $CO_2$ are released and at $b$ different stages $2H^+$ and $c$ electrons are released. Identify $a, b, c$.

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