When a balanced die is thrown,find the probab | vedclass

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(A) The total outcomes when a balanced die is thrown are $S = \{1, 2, 3, 4, 5, 6\}$.The total number of outcomes is $n(S) = 6$.$A$ composite number is

Vedclass · Accepted Answer

$1/3$

Vedclass · Answer

(A) The total outcomes when a balanced die is thrown are $S = \{1, 2, 3, 4, 5, 6\}$.The total number of outcomes is $n(S) = 6$.$A$ composite number is a positive integer greater than $1$ that has at least one divisor other than $1$ and itself.In the set $\{1, 2, 3, 4, 5, 6\}$,the composite numbers are $4$ and $6$.Thus,the favorable outcomes are $E = \{4, 6\}$.The number of favorable outcomes is $n(E) = 2$.The probability $P(E)$ is given by $\frac{n(E)}{n(S)} = \frac{2}{6} = \frac{1}{3}$.

Test Number	Marks obtained
$1$	$62$
$2$	$72$
$3$	$78$
$4$	$91$
$5$	$85$

When a balanced die is thrown,find the probability of receiving a composite number.

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