When a certain metal surface is illuminated with light of wavelength $\lambda$,the stopping potential is $V$. When the same surface is illuminated by light of wavelength $2\lambda$,the stopping potential is $\frac{V}{3}$. The threshold wavelength for the surface is:

  • A
    $\frac{8\lambda}{3}$
  • B
    $\frac{4\lambda}{3}$
  • C
    $4\lambda$
  • D
    $6\lambda$

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