When a gas expands adiabatically,

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For an adiabatic process,the heat exchange $\Delta Q = 0$.According to the first law of thermodynamics,$\Delta Q = \Delta U + \Delta W$.Since $\De

Vedclass · Accepted Answer

Internal energy of the gas is used in doing work

Vedclass · Answer

(C) For an adiabatic process,the heat exchange $\Delta Q = 0$.According to the first law of thermodynamics,$\Delta Q = \Delta U + \Delta W$.Since $\Delta Q = 0$,we have $0 = \Delta U + \Delta W$,which implies $\Delta W = -\Delta U$.When a gas expands,it does work on the surroundings,so $\Delta W > 0$.Consequently,$\Delta U$ must be negative,meaning the internal energy of the gas decreases as it is used to perform work.

Similar Questions

$P-V$ plots for two gases during an adiabatic process are shown. Plots $(1)$ and $(2)$ correspond to

The amount of work done in an adiabatic expansion from temperature $T$ to ${T_1}$ is

At $27^\circ C$,a gas is suddenly compressed such that its pressure becomes $1/8$th of the original pressure. The temperature of the gas will be $(\gamma = 5/3)$.

$A$ diatomic gas initially at $18^oC$ is compressed adiabatically to one-eighth of its original volume. The temperature after compression will be

$A$ cycle tyre bursts suddenly. What is the type of this process?

Vedclass Test Series

Exam Paper Generator

Online Exam Module