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(C) The formula for capillary rise is given by $h = \frac{2S \cos 	heta}{ho gr}$.Rearranging for surface tension $S$,we get $S = \frac{ho grh}{2

Vedclass · Accepted Answer

$101$

Vedclass · Answer

(C) The formula for capillary rise is given by $h = \frac{2S \cos 	heta}{ho gr}$.Rearranging for surface tension $S$,we get $S = \frac{ho grh}{2 \cos 	heta}$.Given values:Radius $r = 0.015 \; cm = 1.5 	imes 10^{-4} \; m$.Height $h = 15 \; cm = 0.15 \; m$.Density $ho = 900 \; kg \; m^{-3}$.Acceleration due to gravity $g = 10 \; ms^{-2}$.Contact angle $	heta = 0^{\circ}$,so $\cos 	heta = 1$.Substituting the values:$S = \frac{900 	imes 10 	imes 0.15 	imes 1.5 	imes 10^{-4}}{2 	imes 1}$$S = \frac{9000 	imes 0.225 	imes 10^{-4}}{2}$$S = \frac{2025 	imes 10^{-4}}{2} = 1012.5 	imes 10^{-4} \; N/m$.Converting to $mN/m$ $(1 \; N/m = 1000 \; mN/m)$:$S = 1012.5 	imes 10^{-4} 	imes 10^3 \; mN/m = 101.25 \; mN/m$.The closest integer is $101$.

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