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(C) Let the maximum height be $H$. The velocity at height $h = H/3$ is $v = 10 \sqrt{2} \, m/s$.At the maximum height,the final velocity $v_f = 0$.Usi

Vedclass · Accepted Answer

$15$

Vedclass · Answer

(C) Let the maximum height be $H$. The velocity at height $h = H/3$ is $v = 10 \sqrt{2} \, m/s$.At the maximum height,the final velocity $v_f = 0$.Using the third equation of motion between the point at height $H/3$ and the maximum height $H$:$v_f^2 = v^2 - 2g \Delta y$Here,$\Delta y = H - H/3 = 2H/3$ and $g = 10 \, m/s^2$.$0^2 = (10 \sqrt{2})^2 - 2 	imes 10 	imes (2H/3)$$0 = 200 - 40H/3$$40H/3 = 200$$H = (200 	imes 3) / 40 = 15 \, m$.Thus,the maximum height attained is $15 \, m$.

When a particle is thrown vertically upwards,its velocity at one third of its maximum height is $10 \sqrt{2} \, m/s$. The maximum height attained by it is .......... $m$.

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