When a piece of a magnetic substance is placed in a uniform magnetic field,the flux density inside it is four times the flux density away from the piece. The magnetic permeability of the material is
- A$1$
- B$2$
- C$3$
- D$4$
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$A$ bar of iron having magnetic moment $2.4 \text{ Am}^2$ weighs $66 \text{ g}$. If the density of the material of the bar is $7700 \text{ kg/m}^3$,the intensity of magnetisation in $\text{Am}^{-1}$ is
Susceptibility of $Mg$ at $300\, K$ is $1.2 \times 10^{-5}$. The temperature at which susceptibility will be $1.8 \times 10^{-5}$ is......$K$.
Medium
View SolutionThe relationship between the magnetic susceptibility $(\chi)$ and the magnetic permeability $(\mu)$ is given by (where $\mu_0$ is the permeability of free space and $\mu_{r}$ is relative permeability).
$ \chi_{1} $ and $ \chi_{2} $ are the magnetic susceptibilities of a paramagnetic material at temperatures $ T_{1} \ K $ and $ T_{2} \ K $ respectively. Then:
According to Curie's law,the magnetic susceptibility of a substance at an absolute temperature $T$ is proportional to
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