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(B) Let the height of the tower be $h$. The distance of the mirror from the foot of the tower is $d = 60 \ m$.The angle subtended by the top of the to

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$60$

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(B) Let the height of the tower be $h$. The distance of the mirror from the foot of the tower is $d = 60 \ m$.The angle subtended by the top of the tower and its image at the eye is $90^\circ$. Since the mirror is horizontal,the angle of elevation of the top of the tower from the mirror is $45^\circ$ (as the total angle is $90^\circ$ and the image is formed at an equal depth below the mirror).From the geometry of the triangle formed by the tower and the mirror,we have:$	an 45^\circ = \frac{	ext{height of tower}}{	ext{distance from tower}} = \frac{h}{60}$Since $	an 45^\circ = 1$,we get:$1 = \frac{h}{60}$$h = 60 \ m$.

When a plane mirror is placed horizontally on a level ground at a distance of $60 \ m$ from the foot of a tower,the top of the tower and its image in the mirror subtend an angle of $90^\circ$ at the eye. The height of the tower will be.....$m$.

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