When a rubber ball is taken to the bottom of a sea of depth $1400 \,m$,its volume decreases by $2 \%$. The Bulk modulus of the rubber ball is .................. $\times 10^8 \,N/m^2$ [density of water is $1 \,g/cc$ and $g=10 \,m/s^2$].

Calculate the stress developed inside a tooth cavity filled with copper when hot tea at a temperature of $57\,^{\circ}C$ is drunk. You can take the body (tooth) temperature to be $37\,^{\circ}C$ and $\alpha = 1.7 \times 10^{-5}/^{\circ}C$,bulk modulus for copper $= 140 \times 10^9\, N/m^2$.

The compressibility of water is $5 \times 10^{-10} \ m^2/N$. $A$ pressure of $15 \times 10^6 \ Pa$ is applied on $100 \ ml$ volume of water. The change in the volume of water is:

When a sphere is taken to the bottom of a sea of depth $1 \ km$,it contracts in volume by $0.01 \%$. The bulk modulus of the material of the sphere is (Acceleration due to gravity $= 10 \ m \ s^{-2}$,density of sea water $= 10^3 \ kg \ m^{-3}$)

The bulk modulus of a liquid is $3 \times 10^{10} \ Nm^{-2}$. The pressure required to reduce the volume of liquid by $2 \%$ is ........ $\times 10^{8} \ Nm^{-2}$.

$A$ sphere contracts in volume by $0.01 \%$ when taken to the bottom of a sea $1 \,km$ deep. Find the Bulk modulus of the material of the sphere in $N/m^2$.