The bulk modulus of a liquid is $3 \times 10^{10} \ Nm^{-2}$. The pressure required to reduce the volume of liquid by $2 \%$ is ........ $\times 10^{8} \ Nm^{-2}$.

When a rubber ball is taken to a depth of $h$ meters in deep sea,its volume decreases by $0.5\, \%$. Calculate the depth $h$. (Given: Bulk modulus of rubber $B = 9.8 \times 10^{8} \, \text{N/m}^2$,Density of sea water $\rho = 10^{3} \, \text{kg/m}^3$,$g = 9.8 \, \text{m/s}^2$)

Bulk modulus was first defined by

What is the bulk modulus of a perfectly rigid body?

When a rubber ball is taken to the bottom of a sea of depth $1400 \,m$,its volume decreases by $2 \%$. The Bulk modulus of the rubber ball is .................. $\times 10^8 \,N/m^2$ [density of water is $1 \,g/cc$ and $g=10 \,m/s^2$].

The density of a metal at normal pressure $P$ is $\varrho$. When it is subjected to an excess pressure $p$,the density becomes $\varrho^{\prime}$. If $K$ is the bulk modulus of the metal,then the ratio $\frac{\varrho^{\prime}}{\varrho}$ is