When a slow neutron goes sufficiently close to a ${U^{235}}$ nucleus,then the process that takes place is

  • A
    Fission of ${U^{235}}$
  • B
    Fusion of neutron
  • C
    Fusion of ${U^{235}}$
  • D
    First $(a)$ then $(b)$

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Similar Questions

Which is more destructive: an atomic bomb or a hydrogen bomb?

What is the energy released by the fission of $1 \, g$ of $U^{235}$?

The disintegration energy $Q$ for the nuclear fission of ${ }^{235} U \rightarrow{ }^{140} Ce+{ }^{94} Zr+n$ is $\_ \text{MeV}$.
Given atomic masses of:
${ }^{235} U: 235.0439 \text{ u}, { }^{140} Ce: 139.9054 \text{ u},$
${ }^{94} Zr: 93.9063 \text{ u}, n: 1.0086 \text{ u},$
Value of $c^2 = 931 \text{ MeV/u}$.

If $200 \text{ MeV}$ of energy is released in the fission of one nucleus of ${ }_{92}^{236} U$, the number of nuclei that must undergo fission to release an energy of $1000 \text{ J}$ is

The fission properties of $_{94}^{239} Pu$ are very similar to those of $_{92}^{235} U$. The average energy released per fission is $180 \; MeV$. How much energy, in $MeV$, is released if all the atoms in $1 \; kg$ of pure $_{94}^{239} Pu$ undergo fission?

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