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Question

(B) According to the Doppler effect,when a source of sound moves towards a stationary observer with velocity $v_s$,the apparent frequency $f'$ is give

Vedclass · Accepted Answer

increases while wavelength decreases.

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(B) According to the Doppler effect,when a source of sound moves towards a stationary observer with velocity $v_s$,the apparent frequency $f'$ is given by $f' = f \left( \frac{v}{v - v_s} \right)$,where $v$ is the speed of sound and $f$ is the actual frequency.Since the denominator $(v - v_s)$ is less than $v$,the apparent frequency $f'$ is greater than the actual frequency $f$,meaning the frequency increases.The wavelength $\lambda'$ observed by the stationary observer is given by $\lambda' = \frac{v - v_s}{f}$. Since $(v - v_s) < v$,the apparent wavelength $\lambda'$ is less than the actual wavelength $\lambda = v/f$. Thus,the wavelength decreases.

When a source of sound moves towards a stationary observer,the apparent frequency heard by him

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