When a wire of uniform cross-section a,length | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) When a wire of resistance $R$ is bent into a circle,it is divided into two equal semicircular parts.Each part has a resistance of $R' = \frac{R}{2

Vedclass · Accepted Answer

$\frac{R}{4}$

Vedclass · Answer

(A) When a wire of resistance $R$ is bent into a circle,it is divided into two equal semicircular parts.Each part has a resistance of $R' = \frac{R}{2}$.These two semicircular parts are connected in parallel between the two diametrically opposite points.The equivalent resistance $R_{eq}$ between these points is given by the parallel combination formula:$\frac{1}{R_{eq}} = \frac{1}{R'} + \frac{1}{R'} = \frac{1}{R/2} + \frac{1}{R/2} = \frac{2}{R} + \frac{2}{R} = \frac{4}{R}$.Therefore,$R_{eq} = \frac{R}{4}$.

When a wire of uniform cross-section $a$,length $l$ and resistance $R$ is bent into a complete circle,what is the resistance between any two diametrically opposite points?

Similar Questions

Two cells of same $emf$ $E$ but internal resistances $r_1$ and $r_2$ are connected in series to an external resistor $R$ (as shown in the figure). What should be the value of $R$ so that the potential difference across the terminals of the first cell becomes zero?

For the given circuit,the potential difference between $x$ and $y$ is ......... (in $V$)

Two wires of thickness $1 \, mm$ and $2 \, mm$ have the same mass of copper. The two wires are connected in series and a current is passed through them. The ratio of the power generated in the wires will be ....

In the given circuit,what is the voltage between $P$ and $Q$ in $V$?

In the circuit shown in the adjoining figure,the reading of ammeter $A$ is ................ $A$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module