When heat energy of 1500 ; J is supplied to a | vedclass

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Question

(C) According to the First Law of Thermodynamics $(FLOT)$,the heat supplied $(\Delta Q)$ is equal to the change in internal energy $(\Delta U)$ plus t

Vedclass · Accepted Answer

$975$

Vedclass · Answer

(C) According to the First Law of Thermodynamics $(FLOT)$,the heat supplied $(\Delta Q)$ is equal to the change in internal energy $(\Delta U)$ plus the work done by the gas $(W = P \Delta V)$.$\Delta Q = \Delta U + P \Delta V$Given:$\Delta Q = 1500 \; J$$P = 2.1 	imes 10^5 \; N/m^2$$\Delta V = 2.5 	imes 10^{-3} \; m^3$Rearranging the formula to find $\Delta U$:$\Delta U = \Delta Q - P \Delta V$$\Delta U = 1500 - (2.1 	imes 10^5) 	imes (2.5 	imes 10^{-3})$$\Delta U = 1500 - (2.1 	imes 2.5 	imes 10^2)$$\Delta U = 1500 - (5.25 	imes 100)$$\Delta U = 1500 - 525$$\Delta U = 975 \; J$Therefore,the increase in internal energy is $975 \; J$.

When heat energy of $1500 \; J$ is supplied to a gas at a constant pressure of $2.1 \times 10^5 \; N/m^2$,its volume increases by $2.5 \times 10^{-3} \; m^3$. The increase in the internal energy of the gas in Joules is ...... $J$.

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